Where is

[Risex4]

Sod off, I'm still on prisoners. Its to do with switch combinations, but I cant figure out what exactly.

 

[classic33]

Sod off, I'm still on prisoners. Its to do with switch combinations, but I cant figure out what exactly.

You asked for it!

 

[Risex4]

God damn you. Its a binary system of on/off to equate to yes/no for each inmate. Its the one switch/random inmate which has me stumped right now.

 

[Moon bunny]

Appoint 1 counter the others are "flippers"
When a flipper visits the room if switch 1 is on flip switch 2
if switch 1 is off and the flipper has seen it on previously, and never flipped it on a previous visit, flip it on, otherwise flip switch 2
If 1 is off and he has previously flipped 1, flip 2.
Counter:
If 1 is off flip it on,
if 1 is on flip it off, if he did not flip it on on his last visit, increase the count of prisoners who have visited the room by 1.

 

[Roadrider48]

No one actually touches the switches.

 

[biggs682]

my daughter had homework about electricity , switches , volts etc etc

 

[Risex4]

Appoint 1 counter the others are "flippers"
When a flipper visits the room if switch 1 is on flip switch 2
if switch 1 is off and the flipper has seen it on previously, and never flipped it on a previous visit, flip it on, otherwise flip switch 2
If 1 is off and he has previously flipped 1, flip 2.
Counter:
If 1 is off flip it on,
if 1 is on flip it off, if he did not flip it on on his last visit, increase the count of prisoners who have visited the room by 1.

I was getting hung up on the unknown starting position of switch 1 and the visits of flippers being outside of control before the first visit of the counter.

 

[nickyboy]

At noon the hour, minute, and second hands coincide. In about one hour and five minutes the minute and hour hands will coincide again.
What is the exact time (to the millisecond) when this occurs, and what angle will they form with the second hand?
(Assume that the clock hands move continuously.)

As the hour and minute hands cross 11 times in any 12 hour period, the time between the crossings is 12 hours/11

So the first crossing that you ask for is 12.00 (Noon) + 12hours/11 = 1hr 5minutes 27.2727r seconds

The prison question is puzzling me. Given the prisoners are chosen at random, there is nothing to prevent an infinite series of the same prisoner being chosen. Or have I misunderstood?

 

[classic33]

As the hour and minute hands cross 11 times in any 12 hour period, the time between the crossings is 12 hours/11

So the first crossing that you ask for is 12.00 (Noon) + 12hours/11 = 1hr 5minutes 27.2727r seconds

The prison question is puzzling me. Given the prisoners are chosen at random, there is nothing to prevent an infinite series of the same prisoner being chosen. Or have I misunderstood?

But at what time does it happen?

Correct with nothing to prevent an infinite series of the same prisoner being chosen. However all must flip one of the two switches at least once.

 

[threebikesmcginty]

STBITGF?

 

[nickyboy]

But at what time does it happen?

Correct with nothing to prevent an infinite series of the same prisoner being chosen. However all must flip one of the two switches at least once.

13.05.272727272727r

And I give in on the prisoner question. I can't make the logic step beyond the scenario of an infinite series which would seem to prevent all the prisoners being chosen at least once. Maybe I need more coffee
Edit: forgot to give the angle. 130.90909r degrees

 

[classic33]

STBITGF?

Make like a turkey at Christmas..

 

[TVC]

44

 

[Pale Rider]

There's a solution online which relies on the appointment of a counter.

However, it also relies on the counter being regularly selected to go into the switch room.

If I read the problem correctly, a single prisoner - in this case the counter - could be selected to go into the switch room once, but never again.

If that's right, the solution doesn't work.

 

[Aperitif]

Make like a turkey at Christmas..

Here's a picture of Turkey at Christmas.
This tree is made of Istanbul's