annirak
Veteran
- Location
- Cambridge, UK
Let's take your scenario and refine it a little.If you don't like my assumptions, say so, change them to something more realistic and do the math. BTW, I've made the assumptions more realistic for you. Compare them to mine.
Two bicycles accelerate from zero to 30 kph in three minutes. Both weigh the same with their riders - 90 kg.
However, bicycle A has wheels that are lighter than bicycle B, by 400 grams for the pair. Obviously bicycle B has the 400 grams placed elsewhere.
That weight saving is shaven of all areas of the wheel, ranging from tyres (radius 368mm) to hub (radius 36mm).
Bicycle B's wheels have a mass of 2500 grams and the mass is evenly distributed from radius 368mm through 36mm.
Most bicycle wheels aren't discs, they're rims with spokes and hubs. There are a few iterations of refinement we can go through, but before we get too complicated, lets just go with a fairly simple model:
A hub, some spokes, a rim.
I'll assume that the rim, tyre, and tube have all their mass concentrated in a cylindrical strip, the radius of the wheel.
For the hub, I'll assume it is a cylinder of uniform density
I'll assume the spokes extend all the way from the centre (straight through the hub, yes) to the rim.
Hubs:
mass = 357g rear, 155g front
radius = 57.9mm
Spokes (32 per wheel)
length: 368mm
mass: 6g
Rim+tyre+tube:
radius = 368mm
mass = 435g (rim) + 105g (tube) + 200g (tyre) = 740g
Total wheel masses:
Front: 1.087kg
Rear: 1.289kg
Moments of intertia:
Cylinder: 1/2MR^2
Rod suspended at one end: 1/3ML^2
Cylindrical thin strip: MR^2
Numeric values (kg*m^2)
Front Hub = 0.000259812
Rear Hub = 0.000598405
One spoke = 0.000270848
Tyre = 0.0270848
Tube = 0.01421952
Rim = 0.05890944
Front Wheel: 0.109140708
Rear Wheel: 0.109479301
This seems to indicate that the moment of inertia of the hub doesn't matter, which is what we'd expect, since it's much smaller in radius than any of the other parts.
Since the inertia of the hub doesn't matter and spokes don't change much, we're going to concentrate that 400g weight savings in the rims.
So bike A has lead shot in the water bottle, and bike B has lead shot in the rims.
KE @ 30kph:
Bike A: 3830J
Bike B: 3844J
Bike B's extra energy requirement to get to 30kph: 14J => 0.36%
Like I said: I disagree with your assumptions, but I agree with your conclusion.