Riddles and Puzzles

[classic33]

Stats was never my strong suit, but I'll give it a shot.

Side bets pays off in case of 2 or more 1's

#1's chance Mr G Mr P CC
0 1*5^5/6^5 -10 5 5
1 5*5^4/6^5 -6 5 1
2 10*5^3/6^5 8 -5 -3
3 10*5^2/6^5 12 -5 -7
4 5*5^1/6^5 16 -5 -11
5 1*5^0/6^5 20 -5 -15

Which gives average payouts to

1) Casino +£1.67
2) Mr Gamble -£4.70
3) Mr Prude +£3.04

Nope.

 

[classic33]

Weird Words
1) What is the longest English word that contains a single, unrepeated vowel?
2) Give 2 9-letter words that have 1 syllable.
3) Give a word that has 5 consecutive vowels.
4) Give 2 words that have 5 consecutive consonants.
5) Give a word that has 6 consecutive consonants
6) Give 2 words that have the 6 vowels a e i o u y in alphabetical order
7) Give a word that has 6 occurrences of the same vowel.

and finally, the one you were waiting for ......

8) Give a word that has three consecutive repeated letters.

 

[classic33]

Somewhat,but they all depend on at least one person being allowed in continuously,which may not happen because the warden may or may not allow them in more than once.So no.
And No.

I've got some idea about the Bet question,i'll see if i can figure it out by evening.

Still no answer! Wednesday morning.


Two Easy Ones!
1) Name the first TV couple to be shown in the same bed together?
2) How many times can you subtract 7 from 83 and what is left after?

 

[Archie_tect]

Morecambe and Wise.
Once and 76, because then you'd be subtracting 7 from 76....

 

[classic33]

Morecambe and Wise.
Once and 76, because then you'd be subtracting 7 from 76....

1 out of 2.

 

[AndyRM]

2) How many times can you subtract 7 from 83 and what is left after?

As many times as you want, you'll always end up with 76.

I've just noticed that my prisoner answer hasn't posted. Must be stuck in my iPad. Boo and hiss!

 

[classic33]

As many times as you want, you'll always end up with 76.

I've just noticed that my prisoner answer hasn't posted. Must be stuck in my iPad. Boo and hiss!

1 out of 2. Same as Archie_tect.

 

[AndyRM]

Oh yeah, the couple is Mary Kay and Johnny.

I had to ask my granddad about that one after a massively frustrating pub quiz. I'd always thought it was Fred and Wilma Flintstone.

 

[classic33]

That'd be four answers now for the second question.
Would being in the same bed, with each having a foot on the floor count though?

 

[AndyRM]

That'd be four answers now for the second question.
Would being in the same bed, with each having a foot on the floor count though?

Eh? I count two for each.

 

[classic33]

Eh? I count two for each.

I had two seperate answers, and another two seperate ones have been given, making four answers for the same.
Thats why I asked about the foot on the floor.

 

[AndyRM]

Oh, right!

A brief scout around the interwebs suggests that my auld yin is right, but there are conflicting claims about whether you actually saw them in the bed. Hmmm.

I'm not sure that the foot thing counts to be honest.

What's your answer?

 

[classic33]

Oh, right!

A brief scout around the interwebs suggests that my auld yin is right, but there are conflicting claims about whether you actually saw them in the bed. Hmmm.

I'm not sure that the foot thing counts to be honest.

What's your answer?

You gave it earlier. Or more precisely, one of the answers I had when asking.

 

[classic33]

Triangle Of Death
Three
men: Fermat,
Galois, and Hilbert,
decide to fight a pistol duel.
They'll stand at the corners of an
equilateral triangle, and each man, in
order, will aim and shoot wherever he pleases.
They choose randomly who will be shooting first,
second, and third, and will continue in order until two
of them are dead. All three know Fermat always hits his
target, Galois is 80% accurate, and Hilbert hits his mark half
the time. Assuming that all three adopt the best strategy and that
nobody is killed by a wild shot not intended for him, who has the best
chance to survive, and why? Find the survival probabilities for each man.

 

[Fnaar]

You are in a room. There are two doors marked A and B. One of these doors leads to freedom, the other leads to certain death.

There are two other men in the room. They both know which door is which. One of them always lies when asked a question, the other always tells the truth when asked a question. You don't know which one lies nor which one tells the truth.

You can ask one question to one of the men, then you must decide which door to leave by

Kick 'em both in the nuts then dash through one of the doors shouting "Banzaiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii!!!!!!!!!!!!!!!!!!"