Nigeyy
Legendary Member
- Location
- Massachusetts, USA
Hmmm. Wish I could laugh at that. I really do.
Your President's maths. Good luck.
Your President's maths. Good luck.
Multiple voting options. It's possible to both not have it and know someone who has.A mathematics question: how can 49 votes out of 51 be 100%?
And it will get much busier.
My son has been sent home from work because of a case in one part of the very large building. The office has sent home anyone with health issues such as lung/chest/cardiac problems or weakened immune systems. Luckily (or unluckily) for him he can do much of his work online so it stops the boredom setting in.
How do we check our body temperature if we don't have thermometers? I'm thinking that most of those new type ones where you point it at the head have been bought up by the selfish stockpilers. Can we go to a health centre to be tested by a 'treatment room' nurse?
How do we check our body temperature if we don't have thermometers? I'm thinking that most of those new type ones where you point it at the head have been bought up by the selfish stockpilers. Can we go to a health centre to be tested by a 'treatment room' nurse?
I'm stealing that as wellTake a 25mm cube of frozen distilled water with a mass of 15g. Tilt your head back until you can't see the internet and balance the cube on your forehead. During fusion, temperature of the ice and thus temperature difference remains constant, 37 ºC - 0 ºC. So heat rate is constant, if you assume a constant heat transfer coefficient h. Therefore, total energy transferred is equal to 0.0015 kg times enthalpy of fusion (J/kg) of water equal to h (W/m2.K) times superficial area A of the ice mass times temperature difference (37 ºC = 37 K) times time t. From this, you get time t. For the mass of 0.0015 kg you get the volume V with density of ice at 0 ºC (slightly less than 1,000 kg/m3). The question is then what it is the area A, which in our case is 375mm squared. I have taken a typical value of heat transfer to ambient by natural convection and thermal radiation h = 10 W/m2K which means the ice cube should melt completely in 76 minutes and 33 seconds assuming you stay perfectly still and facing away from the internet. If it melts quicker than this, your temperature is elevated.
Get back to us and let us know how you get on.
Just got back from the health centre. I have a temp'of 150F and been sent home to self isolate!!!😥Take a 25mm cube of frozen distilled water with a mass of 15g. Tilt your head back until you can't see the internet and balance the cube on your forehead. During fusion, temperature of the ice and thus temperature difference remains constant, 37 ºC - 0 ºC. So heat rate is constant, if you assume a constant heat transfer coefficient h. Therefore, total energy transferred is equal to 0.0015 kg times enthalpy of fusion (J/kg) of water equal to h (W/m2.K) times superficial area A of the ice mass times temperature difference (37 ºC = 37 K) times time t. From this, you get time t. For the mass of 0.0015 kg you get the volume V with density of ice at 0 ºC (slightly less than 1,000 kg/m3). The question is then what it is the area A, which in our case is 375mm squared. I have taken a typical value of heat transfer to ambient by natural convection and thermal radiation h = 10 W/m2K which means the ice cube should melt completely in 76 minutes and 33 seconds assuming you stay perfectly still and facing away from the internet. If it melts quicker than this, your temperature is elevated.
Get back to us and let us know how you get on.