MrJamie
Oaf on a Bike
It's not so much that the wheel falls out, as much as the force from the disc brake being applied pushes the wheel down and the caliper hence left fork upwards almost as if the wheel were rotating around the caliper, as far as I understand. This is one of the best all round explanations and linked to by Sheldon Brown on his Skewers page when he talked about the problem http://www.ne.jp/asahi/julesandjames/home/disk_and_quick_release/#slipping Its basically a massive force levering the wheel out of the dropouts, more than the skewers need to be rated for to meet standards. So everytime you brake on a front disc brake (with caliper behind the fork) its trying hard to eject the wheel from the forks. Even with the lips on the dropouts, supposedly the dropout can sheer or the skewer can fail enough that the force will push it out. Im fairly sure that what mine was doing was pushing the wheel out until it hit that lip, but the lip was doing enough to keep it in. Presumably a suspension fork would be easier to jump out of too.how can that happen? fork drop outs are recessed so that even when the skewer is undone, the wheel cannot drop out.
There's loads of articles about it, but i guess given the proliferation of disc brakes it cant be that common to actually result in serious injury. If you google "disc brakes quick release" youll find countless articles/posts about it and loads of information.