Bigtallfatbloke
New Member
A cat would solve this problem faster!
No it doesn't. You misunderstand. As Patrick said, under certain conditions the flying bird would exert force on the bottom of the box.
cisamcgu said:So - when the lid is closed, the scales will measure the both the bird and the box, irrespective of if it is flying or not(mass or weight, bonj - I know the difference, and it doesn't matter in this case (I think lol))
But what happens when the lid is opened, but the bird is still flying in the box ? (Hummingbird is better than canary)
Andrew
mosschops2 said:1010g, lid shut, canary standing. Fine
When the canary is hovering / flying in circles, the box will weigh in at 1000g, and the slight force on the air on the scales will register also - like when you get lab scales - even breathing can affect the reading. But it will be 1000g plus a tiny amount - say 1001g +/- 1 g.
(ie not 1009g +/- 1g)
Friction (wings against air).Patrick Stevens said:One interesting factor is that the box would heat up. I'll let bonj explain why.
Friction (wings against air).Elmer Fudd;40242][quote name= said:One interesting factor is that the box would heat up. I'll let bonj explain why.
bonj said:Hmmm... you've got to think outside the box for this one.
Why do you think it would heat up Patrick? I'm not sure it would, although will listen to your reasoning with an open mind if you think it would...I suppose there would be friction between its wings and the air but that would be miniscule/insignificant to the actual box itself.
OK, here's another conundrum. (I know the answer to this.) Given that mosschops is right that the reading on the scales would be, say, 1001g +/- 1g, which I think he is, then how would you determine the (fairly) exact mass of the bird WITHOUT unsealing the box?
By unsealing it I mean rendering it a non-closed system, i.e. the air inside it is just part of the atmosphere.